

MCQOPTIONS
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1. |
For the block diagram shown below :The characteristic equation is |
A. | τl S (τps + 1) + Kc . Kp (τlS + 1) e-τd s = 0 |
B. | (τmS + 1) (τpS + 1) + Km . Kp e-τd S = 0 |
C. | τl S(τm S + 1) (τp S + 1) +Kc . Kp . Km (τl s + 1) e-τdS = 0 |
D. | (τms + 1) (τp s + 1) + Kc . Kp . Km . e-τdS = 0 |
Answer» D. (œÑms + 1) (œÑp s + 1) + Kc . Kp . Km . e-œÑdS = 0 | |