For given BJT, =200. The applied input frequency is 20 Mhz and net in – McqOptions

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1.	For given BJT, =200. The applied input frequency is 20 Mhz and net internal capacitance is 100 pF. What is the CE short circuit current gain at cut-off frequency?
A.	200
B.	100
C.	141.42
D.	440.2
Answer» D. 440.2

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