1.

For Boston method, ln Kbj

A. A<sub>j</sub> + B (1<sub>j</sub>/T<sub>j</sub> – 1/T*)
B. A<sub>j</sub> – B (1<sub>j</sub>/T<sub>j</sub> – 1/T*)
C. A<sub>j</sub> – B (1<sub>j</sub>/T<sub>j</sub> + 1/T*)
D. (1<sub>j</sub>/T<sub>j</sub> + 1/T*)
Answer» C. A<sub>j</sub> ‚Äö√Ñ√∂‚àö√ë‚àö¬® B (1<sub>j</sub>/T<sub>j</sub> + 1/T*)


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