1.

For \[A=133{}^\circ ,\ 2\cos \frac{A}{2}\]is equal to [DCE 2001]

A. \[-\sqrt{1+\sin A}-\sqrt{1-\sin A}\]
B. \[-\sqrt{1+\sin A}+\sqrt{1-\sin A}\]
C. \[\sqrt{1+\sin A}-\sqrt{1-\sin A}\]
D. \[\sqrt{1+\sin A}+\sqrt{1-\sin A}\]
Answer» D. \[\sqrt{1+\sin A}+\sqrt{1-\sin A}\]


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