1.

Find the value of ∫tan-1⁡(x)dx.

A. sec-1 (x) – 1⁄2 ln⁡(1 + x2)
B. xtan-1 (x) – 1⁄2 ln⁡(1 + x2)
C. xsec-1 (x) – 1⁄2 ln⁡(1 + x2)
D. tan-1 (x) – 1⁄2 ln⁡(1 + x2)
Answer» C. xsec-1 (x) – 1⁄2 ln⁡(1 + x2)


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