Find the value of \(\int \frac{1}{16x^2+16x+10}dx\). – McqOptions

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1.	Find the value of \(\int \frac{1}{16x^2+16x+10}dx\).
A.	1⁄8 sin-1(x + 1⁄2)
B.	1⁄8 tan-1(x + 1⁄2)
C.	1⁄8 sec-1(x + 1⁄2)
D.	1⁄4 cos-1(x + 1⁄2)
Answer» C. 1⁄8 sec-1(x + 1⁄2)

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