Find the value of \(\int\int_0^y \frac{2xy^5}{\sqrt{1+x^2 y^2-y^4}} d

1.	Find the value of $\int\int_0^y \frac{2xy^5}{\sqrt{1+x^2 y^2-y^4}} dxdy$.
A.	$2[\frac{y^4}{4}- \frac{2}{3} (1-y^4)^{\frac{3}{2}}]$
B.	$2[\frac{y^4}{4}- (1-y^4)^{\frac{3}{2}}]$
C.	$2[\frac{y^4}{4}-\frac{2}{3} (1-y^4)^{\frac{3}{2}}]$
D.	$2[\frac{y^3}{3}-\frac{2}{3} (1-y^4)^{\frac{3}{2}}]$
Answer» D. $2[\frac{y^3}{3}-\frac{2}{3} (1-y^4)^{\frac{3}{2}}]$

Discussion

1.	Find the value of \(\int\int_0^y \frac{2xy^5}{\sqrt{1+x^2 y^2-y^4}} dxdy\).
A.	\(2[\frac{y^4}{4}- \frac{2}{3} (1-y^4)^{\frac{3}{2}}]\)
B.	\(2[\frac{y^4}{4}- (1-y^4)^{\frac{3}{2}}]\)
C.	\(2[\frac{y^4}{4}-\frac{2}{3} (1-y^4)^{\frac{3}{2}}]\)
D.	\(2[\frac{y^3}{3}-\frac{2}{3} (1-y^4)^{\frac{3}{2}}]\)
Answer» D. \(2[\frac{y^3}{3}-\frac{2}{3} (1-y^4)^{\frac{3}{2}}]\)