1.

Find the particular solution of the differential equation \(\frac{dy}{dx}+8x=16x^2+4\) given that y=\(\frac{1}{3}\) when x=1.

A. y=\(\frac{(2x+1)^2}{3}\)
B. y=\(\frac{(4x+1)^2}{12}\)
C. y=\(\frac{(4x-2)^2}{3}\)
D. y=\(\frac{(2x-1)^2}{3}\)
Answer» E.


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