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1. |
Find the normalization transformation that maps a window whose lower left corner is at (1,1) and upper right corner is at (3, 5) onto a viewport that is the entire normalized device screen. |
A. | \(\left( {\begin{array}{*{20}{c}} {\frac{1}{2}}&0&{ - \frac{1}{2}}\\ 0&{\frac{1}{4}}&{ - \frac{1}{4}}\\ 0&0&1 \end{array}} \right)\) |
B. | \(\left( {\begin{array}{*{20}{c}} {\frac{1}{2}}&0&{\frac{1}{2}}\\ 0&{ - \frac{1}{4}}&{\frac{1}{4}}\\ 1&1&1 \end{array}} \right)\) |
C. | \(\left( {\begin{array}{*{20}{c}} {\frac{1}{2}}&0&{ - \frac{1}{2}}\\ 0&{\frac{1}{4}}&{\frac{1}{4}}\\ 1&0&0 \end{array}} \right)\) |
D. | \(\left( {\begin{array}{*{20}{c}} {\frac{1}{2}}&0&{\frac{1}{2}}\\ 0&{\frac{1}{4}}&{ - \frac{1}{4}}\\ 1&0&0 \end{array}} \right)\) |
Answer» B. \(\left( {\begin{array}{*{20}{c}} {\frac{1}{2}}&0&{\frac{1}{2}}\\ 0&{ - \frac{1}{4}}&{\frac{1}{4}}\\ 1&1&1 \end{array}} \right)\) | |