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1. |
Find the minimum value of swaying couple in newtons from the following data:m = 100Kgω = 300 rpmradius = 0.6mc = 2/3a = 2\(\sqrt{2}\)m |
A. | -6978 |
B. | -7574 |
C. | -6568 |
D. | - 7374 |
Answer» B. -7574 | |