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1. |
Find the inverse Laplace transform for X(s) = \(ln (\frac{s+a}{s+b})\). |
A. | \(\frac{e^{-at} – e^{-bt}}{t}\) |
B. | \(\frac{e^{-bt} – e^{-at}}{t}\) |
C. | \(\frac{e^{-at} + e^{-bt}}{t}\) |
D. | \(\frac{e^{bt} + e^{-at}}{t}\) |
Answer» C. \(\frac{e^{-at} + e^{-bt}}{t}\) | |