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1. |
Find the integral of \(3e^x+\frac{2(log x)}{3x}\). |
A. | \(3e^x+\frac{1}{3} (x)^2+C\) |
B. | \(e^x-\frac{8}{3} (logx)^2+C\) |
C. | \(3e^x-\frac{1}{3} (logx)^2+C\) |
D. | \(3e^x+\frac{1}{3} (logx)^2+C\) |
Answer» E. | |