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1. |
Find the complementary current from the information provided in the question 4. |
A. | i<sub>c</sub> = e<sup>-37.5t</sup>(c<sub>1</sub>cos1290t + c<sub>2</sub>sin1290t) |
B. | i<sub>c</sub> = e<sup>-37.5t</sup>(c<sub>1</sub>cos1290t – c<sub>2</sub>sin1290t) |
C. | i<sub>c</sub> = e<sup>37.5t</sup>(c<sub>1</sub>cos1290t – c<sub>2</sub>sin1290t) |
D. | i<sub>c</sub> = e<sup>37.5t</sup>(c<sub>1</sub>cos1290t + c<sub>2</sub>sin1290t) |
Answer» B. i<sub>c</sub> = e<sup>-37.5t</sup>(c<sub>1</sub>cos1290t ‚Äö√Ñ√∂‚àö√ë‚àö¬® c<sub>2</sub>sin1290t) | |