MCQOPTIONS
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| 1. |
Find the change in concentration for a steady state equimolar counter diffusion if D(AB)= 6 sq.m/sec, the change in distance is 2 m and the N flux of A is 5 mol/sq.m sec. |
| A. | 0.67 |
| B. | 1.67 |
| C. | 2.67 |
| D. | None of the mentioned |
| Answer» C. 2.67 | |