Find \(lt_{n\rightarrow\infty}\frac{(1^a+2^a+…+(n-1)^a)}{n^{a+1}}\)

1.	Find \(lt_{n\rightarrow\infty}\frac{(1^a+2^a+…+(n-1)^a)}{n^{a+1}}\)
A.	1
B.	1⁄a + 1
C.	0
D.	Undefined
Answer» C. 0

Discussion

Find \(=lt_{x\rightarrow 0}\frac{(a_nx^n+a_{n-1}x^{n-1}+…+a_1x+a_0)}{(b_nx^n+b_{n-1}x^{n-1}+…+b_1x+b_0)}\)
Find \(lt_{x\rightarrow 0}\frac{sin(sin(x))}{x}\)
Find \(lt_{x\rightarrow 0}\frac{sin((4x^3)tan^{-1}(x))}{x^4}\)
Find \(lt_{x\rightarrow -5}(\frac{tan^{-1}(x^2+6x+5)}{x^2+15x+50})\)
Find \(lt_{x\rightarrow -101}(\frac{ln(x^2+20x+(x+101)^2(x^2+3))-ln(x^2+20x)}{x^2+202x+10201})\).
Find \(lt_{n\rightarrow\infty}\frac{(1^a+2^a+…+(n-1)^a)}{n^{a+1}}\)
Find \(lt_{n\rightarrow\infty}\sum_{a=1}^{n-1}(\frac{ln(1+\frac{a}{n})}{n})\)
Find \(lt_{x\rightarrow -2}(\frac{sin((x-2)^2)}{(x+2)^2})\)
Find ltn → ∞\(\sum_{a=0}^{n-1}\frac{sin(\frac{a}{n})}{n}\)
Find lt x → ∞\((\frac{ln(1+\frac{(x+3)^3(2x+9)}{(4x^3+3)})}{x^3+3x^2+9x+27})\)