FeO (s) + CO (g) = Fe (s) + CO2 (g), k = 0. 435 at 1173E; at equilibrium, what will be the number of moles of CO gas required to reduce one mole of FeO at 1173 K?

FeO (s) + CO (g) = Fe (s) + CO2 (g), k = 0. 435 at 1173E; at equilibri

1.	FeO (s) + CO (g) = Fe (s) + CO2 (g), k = 0. 435 at 1173E; at equilibrium, what will be the number of moles of CO gas required to reduce one mole of FeO at 1173 K?
A.	1.0
B.	1.3
C.	2.3
D.	3.3
Answer» E.