f(x) = ( frac{sin(x)}{x} ), How many points exist such that f'(c) = 0 – McqOptions

MCQOPTIONS

1.	f(x) = ( frac{sin(x)}{x} ), How many points exist such that f'(c) = 0 in the interval [0, 18 ].
A.	18
B.	17
C.	8
D.	9
Answer» B. 17

Discussion

No Comment Found

Related MCQs

If the domain of a function can be broken into infinite number of disjoint subsets such that every subset has a Rolles point then the function cannot be in a polynomial structure.
For any second degree polynomial with two real unequal roots. The relation between Rolles point r<sub>1</sub> and the two roots r<sub>2</sub> is
For second degree polynomial it is seen that the roots are equal. Then what is the relation between the Rolles point c and the root x?
For all second degree polynomials with y = ax<sup>2</sup> + bx + k, it is seen that the Rolles point is at c = 0. Also the value of k is zero. Then what is the value of b?
For some function f(x) we have f(a) = f(b) for a,b .I and a + b = 2 then which of the following even degree polynomials could f(x) be
A Function f(x) has the property f(a) = f(b) for a,b .I and a + b = 20 then which of the following even degree polynomials could be f(x)?
Let f(x) = x + sin(x) Every point on the graph is rotated by 45 degree with respect to the origin along the radius equal to the radius vector at that point. How many c that belong to [0, 11 ] exist Such that f'(c) = 0.
f(x) = ( frac{sin(x)}{x} ), How many points exist such that f'(c) = 0 in the interval [0, 18 ].
For the function f(x) = ( frac{sin(x)}{x^2} ) How many points exist in the interval [0, 7 ] Such that f'(c) = 0.
For y = -x<sup>2</sup> + 2x there exist a c in the interval [- 19765, 19767] Such that f'(c) = 0.