Express $\tau_{yz}$ in terms of velocity gradients.

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$\tau_{yz}=μ(\frac{\partial v}{\partial z}+\frac{\partial w}{\partial y})$

TuteeHUB · Answer

$\tau_{yz}=μ(\frac{\partial u}{\partial z}+\frac{\partial u}{\partial y})$

TuteeHUB · Answer

$\tau_{yz}=μ(\frac{\partial v}{\partial x}+\frac{\partial w}{\partial x})$

TuteeHUB · Answer

$\tau_{yz}=μ(\frac{\partial w}{\partial z}+\frac{\partial v}{\partial y})$

1.	Express \(\tau_{yz}\) in terms of velocity gradients.
A.	\(\tau_{yz}=μ(\frac{\partial v}{\partial z}+\frac{\partial w}{\partial y})\)
B.	\(\tau_{yz}=μ(\frac{\partial u}{\partial z}+\frac{\partial u}{\partial y})\)
C.	\(\tau_{yz}=μ(\frac{\partial v}{\partial x}+\frac{\partial w}{\partial x})\)
D.	\(\tau_{yz}=μ(\frac{\partial w}{\partial z}+\frac{\partial v}{\partial y})\)
Answer» B.

Express \(\tau_{yz}\) in terms of velocity gradients.