Expand ln(x) in the power of (x-m).

Question

TuteeHUB · Accepted Answer

ln u2061(m)-  (  frac{h}{m}-  frac{1}{2!} (h/m)^2-  frac{2}{3!} (h/m)^3-    )

TuteeHUB · Answer

ln u2061(m)+  (  frac{h}{m}-  frac{1}{2!} (h/m)^2+  frac{2}{3!} (h/m)^3-    )

TuteeHUB · Answer

ln u2061(m)-  (  frac{h}{m}-  frac{1}{2!} (h/m)^2-  frac{2}{3!} (h/m)^3-    )

TuteeHUB · Answer

ln u2061(m)-  (  frac{1}{2!} (h/m)^2+  frac{2}{3!} (h/m)^4-    )

TuteeHUB · Answer

ln u2061(m)+  (  frac{h}{m}+  frac{2}{3!} (h/m)^3-    )

1.	Expand ln(x) in the power of (x-m).
A.	ln u2061(m)+ ( frac{h}{m}- frac{1}{2!} (h/m)^2+ frac{2}{3!} (h/m)^3- )
B.	ln u2061(m)- ( frac{h}{m}- frac{1}{2!} (h/m)^2- frac{2}{3!} (h/m)^3- )
C.	ln u2061(m)- ( frac{1}{2!} (h/m)^2+ frac{2}{3!} (h/m)^4- )
D.	ln u2061(m)+ ( frac{h}{m}+ frac{2}{3!} (h/m)^3- )
Answer» B. ln u2061(m)- ( frac{h}{m}- frac{1}{2!} (h/m)^2- frac{2}{3!} (h/m)^3- )

Discussion