

MCQOPTIONS
Saved Bookmarks
1. |
Equation of the tangent to the circle \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}\]which is perpendicular to the straight line \[y=mx+c\]is |
A. | \[y=-\frac{x}{m}\pm a\sqrt{1+{{m}^{2}}}\] |
B. | \[x+my=\pm \text{ }a\text{ }\sqrt{1+{{m}^{2}}}\] |
C. | \[x+my=\pm a\sqrt{1+{{(1/m)}^{2}}}\] |
D. | \[x-my=\pm a\sqrt{1+{{m}^{2}}}\] |
Answer» C. \[x+my=\pm a\sqrt{1+{{(1/m)}^{2}}}\] | |