1.

Equation of the tangent to the circle \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}\]which is perpendicular to the straight line \[y=mx+c\]is

A. \[y=-\frac{x}{m}\pm a\sqrt{1+{{m}^{2}}}\]
B. \[x+my=\pm \text{ }a\text{ }\sqrt{1+{{m}^{2}}}\]
C. \[x+my=\pm a\sqrt{1+{{(1/m)}^{2}}}\]
D. \[x-my=\pm a\sqrt{1+{{m}^{2}}}\]
Answer» C. \[x+my=\pm a\sqrt{1+{{(1/m)}^{2}}}\]


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