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1. |
Equation of the latus rectum of the hyperbola\[{{(10x-5)}^{2}}+{{(10y-2)}^{2}}=9{{(3x+4y-7)}^{2}}\] is |
A. | \[y-\frac{1}{5}=-\frac{3}{4}\left( x-\frac{1}{2} \right)\] |
B. | \[x-\frac{1}{5}=-\frac{3}{4}\left( y-\frac{1}{2} \right)\] |
C. | \[y+\frac{1}{5}=-\frac{3}{4}\left( x+\frac{1}{2} \right)\] |
D. | \[x+\frac{1}{5}=-\frac{3}{4}\left( y+\frac{1}{2} \right)\] |
Answer» B. \[x-\frac{1}{5}=-\frac{3}{4}\left( y-\frac{1}{2} \right)\] | |