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do-while loop terminates when conditional expressi...
1.
do-while loop terminates when conditional expression returns?
A.
One
B.
Zero
C.
Non - zero
D.
None of the above
Answer» C. Non - zero
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When 1 is entered, The output of the code below is? #include void main() { int ch; printf("enter a value btw 1 to 2:"); scanf("%d", &ch); switch (ch, ch + 1) { case 1: printf("1 n"); break; case 2: printf("2"); break; } }
When 1 is entered, The output of the code below is? #include void main() { int ch; printf("enter a value btw 1 to 2:"); scanf("%d", &ch); switch (ch) { case 1: printf("1 n"); default: printf("2 n"); } }
When 2 is entered, The output of the code below is? #include void main() { int ch; printf("enter a value btw 1 to 2:"); scanf("%d", &ch); switch (ch) { case 1: printf("1 n"); break; printf("Hi"); default: printf("2 n"); } }
The output of the code below is #include void main() { char *ch; printf("enter a value btw 1 to 3:"); scanf("%s", ch); switch (ch) { case "1": printf("1"); break; case "2": printf("2"); break; } }
The output of the code below is #include void main() { double ch; printf("enter a value btw 1 to 2:"); scanf("%lf", &ch); switch (ch) { case 1: printf("1"); break; case 2: printf("2"); break; } }
The output of the code below is #include void main() { int x = 0; if (x == 0) printf("hi"); else printf("how are u"); printf("hello"); }
Comment on the following code below #include void main() { int x = 5; if (true); printf("hello"); }
The output of the code below is #include int x; void main() { if (x) printf("hi"); else printf("how are u"); }
c = (n) ? a : b; can be rewritten asexp1 ? exp2 : exp3;
do-while loop terminates when conditional expression returns?
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