DIRECTIONS: Reade the following passage and answer the questions that follow. PASSAGE - 1 If \[=P{{\left( 1+\frac{R}{100} \right)}^{n}}\] is the value of an article at certain time which increases at the rate of \[=\frac{R}{{{\left( 1+\frac{R}{100} \right)}^{n}}}\]for first \[{{R}_{1}}%\]years and decreases at the rate of \[{{R}_{2}}%\] for next \[=P\left( 1+\frac{{{R}_{1}}}{100} \right)\times \left( 1+\frac{{{R}_{2}}}{100} \right).\] years, then the value of the article V at the end of \[=P{{\left( 1-\frac{R}{100} \right)}^{n}}.\] years is given by \[=\frac{P}{{{\left( 1-\frac{R}{100} \right)}^{n}}}\] The production of an article of a company in 2002 was 10000. Due to increase in demand, the company increased its production by 20% in the next 2 years. After 2 years due to decrease in the demand, the company decreased its production by 10% in the next year, then the production after 3 years is

DIRECTIONS: Reade the following passage and answer the questions that

1.	DIRECTIONS: Reade the following passage and answer the questions that follow. PASSAGE - 1 If \[=P{{\left( 1+\frac{R}{100} \right)}^{n}}\] is the value of an article at certain time which increases at the rate of \[=\frac{R}{{{\left( 1+\frac{R}{100} \right)}^{n}}}\]for first \[{{R}_{1}}%\]years and decreases at the rate of \[{{R}_{2}}%\] for next \[=P\left( 1+\frac{{{R}_{1}}}{100} \right)\times \left( 1+\frac{{{R}_{2}}}{100} \right).\] years, then the value of the article V at the end of \[=P{{\left( 1-\frac{R}{100} \right)}^{n}}.\] years is given by \[=\frac{P}{{{\left( 1-\frac{R}{100} \right)}^{n}}}\] The production of an article of a company in 2002 was 10000. Due to increase in demand, the company increased its production by 20% in the next 2 years. After 2 years due to decrease in the demand, the company decreased its production by 10% in the next year, then the production after 3 years is
A.	12950
B.	12000
C.	12900
D.	12960
Answer» E.