Differentiate (log⁡2x)sin⁡3x with respect to x.

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

(3 cos⁡3x log⁡(log⁡2x)+$\frac{sin⁡3x}{x log⁡2x}$)

TuteeHUB · Answer

$log⁡2x^{sin⁡3x} \,(3 \,cos⁡3x \,log⁡(log⁡2x)+\frac{sin⁡3x}{x \,log⁡2x})$

TuteeHUB · Answer

–$(3 \,cos⁡3x \,log⁡(log⁡2x)+\frac{sin⁡3x}{x log⁡2x})$

TuteeHUB · Answer

$\frac{3 \,cos⁡3x \,log⁡(log⁡2x)+\frac{sin⁡3x}{x log⁡2x}}{log⁡2x^{sin⁡3x}}$

1.	Differentiate (log⁡2x)sin⁡3x with respect to x.
A.	(3 cos⁡3x log⁡(log⁡2x)+\(\frac{sin⁡3x}{x log⁡2x}\))
B.	\(log⁡2x^{sin⁡3x} \,(3 \,cos⁡3x \,log⁡(log⁡2x)+\frac{sin⁡3x}{x \,log⁡2x})\)
C.	–\((3 \,cos⁡3x \,log⁡(log⁡2x)+\frac{sin⁡3x}{x log⁡2x})\)
D.	\(\frac{3 \,cos⁡3x \,log⁡(log⁡2x)+\frac{sin⁡3x}{x log⁡2x}}{log⁡2x^{sin⁡3x}}\)
Answer» C.

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