

MCQOPTIONS
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1. |
Cutoff frequency fC for TEM mode of propagation is: |
A. | Fc= (2n-1)c/4d√εr -1 |
B. | Fc= (2n-c)/2d(√εr-1) |
C. | Fc= (2n-1)/4d(√εr) |
D. | Fc= (2n-1)/8d√εr – 1 |
Answer» B. | |