Consider the following proposed solution for the critical section problem. There are n processes: P0 ...Pn - 1. In the code, function pmax returns an integer not smaller than any of its arguments. For all i, t[i] is initialized to zero. Code for Pi: do { c[i] = 1; t[i] = pmax (t[0],..., t[n 1]) + 1; c[i] = 0; for every j i in{0,..., n 1} { while(c[j]); while(t[j] != 0 && t[j]

The bounded wait condition is satisfied.

At most one process can be in the critical section at any time.

The bounded wait condition is satisfied.

The progress condition is satisfied.

Consider the following proposed solution for the critical section prob

1.	Consider the following proposed solution for the critical section problem. There are n processes: P0 ...Pn - 1. In the code, function pmax returns an integer not smaller than any of its arguments. For all i, t[i] is initialized to zero. Code for Pi: do { c[i] = 1; t[i] = pmax (t[0],..., t[n 1]) + 1; c[i] = 0; for every j i in{0,..., n 1} { while(c[j]); while(t[j] != 0 && t[j]
A.	At most one process can be in the critical section at any time.
B.	The bounded wait condition is satisfied.
C.	The progress condition is satisfied.
D.	It cannot cause a deadlock.
Answer» B. The bounded wait condition is satisfied.

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