Consider the following proposed solution for the critical section problem. There are n processes: P0…Pn – 1. In the code, function pmax returns an integer not smaller than any of its arguments. For all i, t[i] is initialized to zero.Code for Pi:do { c [i]=1; t[i] = pmax (t [0],…, t[n-1]) +1; c[i]=0; for every j ≠ I in {0,…,n-1} { while (c[j]); while (t[j] != 0 && t[j]

The bounded wait condition is satisfied

At most one process can be in the critical section at any time

The progress condition is satisfied

Consider the following proposed solution for the critical section prob

1.	Consider the following proposed solution for the critical section problem. There are n processes: P0…Pn – 1. In the code, function pmax returns an integer not smaller than any of its arguments. For all i, t[i] is initialized to zero.Code for Pi:do { c [i]=1; t[i] = pmax (t [0],…, t[n-1]) +1; c[i]=0; for every j ≠ I in {0,…,n-1} { while (c[j]); while (t[j] != 0 && t[j]
A.	At most one process can be in the critical section at any time
B.	The bounded wait condition is satisfied
C.	The progress condition is satisfied
D.	It cannot cause a deadlock
Answer» B. The bounded wait condition is satisfied

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