Consider the following equations of two alternating sinusoidal voltages having the same angular frequency ωe1 = 2 sin (ωt)\({e_2} = 6\sqrt 2 \sin \left( {\omega t + \frac{\pi }{4}} \right)\;\)The equation for the resultant voltage is given by:

• A. \({e_r} = 8.71\sin \left\{ {\omega t + {{\tan }^{ - 1}}\frac{1}{{3\sqrt 2 }}} \right\}V\)
• B. \({e_r} = 10\sin \left\{ {\omega t + {{\tan }^{ - 1}}\frac{3}{4}} \right\}V\)
• C. \({e_r} = 8.71\sin \left\{ {\omega t + {{\tan }^{ - 1}}\left( {3\sqrt 2 } \right)} \right\}V\)
• D. \({e_r} = 10\sin \left\{ {\omega t + {{\tan }^{ - 1}}\frac{4}{3}} \right\}V\)