Consider the C functions foo and bar given below:Int foo (int val) {int x = 0;while (val 0)x = x + foo (val --);}return val;}int bar (int val) {int x = 0;while (val 0) {x = x + bar (val – 1);}return val;}Invocations of foo (3) and bar (3) will result in:

Question

Consider the C functions foo and bar given below:Int foo (int val) {int x = 0;while (val > 0)x = x + foo (val --);}return val;}int bar (int val) {int x = 0;while (val > 0) {x = x + bar (val – 1);}return val;}Invocations of foo (3) and bar (3) will result in:

TuteeHUB · Accepted Answer

Both terminating abnormally.

TuteeHUB · Answer

Return of 6 and 6 respectively.

TuteeHUB · Answer

Infinite loop and abnormal termination respectively.

TuteeHUB · Answer

Abnormal termination and infinite loop respectively.

1.	Consider the C functions foo and bar given below:Int foo (int val) {int x = 0;while (val > 0)x = x + foo (val --);}return val;}int bar (int val) {int x = 0;while (val > 0) {x = x + bar (val – 1);}return val;}Invocations of foo (3) and bar (3) will result in:
A.	Return of 6 and 6 respectively.
B.	Infinite loop and abnormal termination respectively.
C.	Abnormal termination and infinite loop respectively.
D.	Both terminating abnormally.
Answer» D. Both terminating abnormally.

Consider the C functions foo and bar given below:Int foo (int val) {int x = 0;while (val > 0)x = x + foo (val --);}return val;}int bar (int val) {int x = 0;while (val > 0) {x = x + bar (val – 1);}return val;}Invocations of foo (3) and bar (3) will result in:

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