Consider a circuit consisting of two capacitors C1 and C2. Let R be the resistance and L be the inductance which are connected in series. Let Q1 and Q2 be the quality factor for the two capacitors. While measuring the Q value by the Series Connection method, the value of the Q factor is?

Question

TuteeHUB · Accepted Answer

Q =   (   frac{(C_2   C_1 ) Q_1 Q_2}{Q_1 C_1   Q_2 C_2}  )

TuteeHUB · Answer

Q =   (  frac{(C_1   C_2 ) Q_1 Q_2}{Q_1 C_1   Q_2 C_2}  )

TuteeHUB · Answer

Q =   (   frac{(C_2   C_1 ) Q_1 Q_2}{Q_1 C_1   Q_2 C_2}  )

TuteeHUB · Answer

Q =   (   frac{(C_1   C_2 ) Q_1 Q_2}{Q_2 C_2   Q_1 C_1}  )

TuteeHUB · Answer

Q =   (   frac{(C_2   C_1 ) C_1 C_2}{Q_1 C_1   Q_2 C_2}  )

1.	Consider a circuit consisting of two capacitors C₁ and C₂. Let R be the resistance and L be the inductance which are connected in series. Let Q₁ and Q₂ be the quality factor for the two capacitors. While measuring the Q value by the Series Connection method, the value of the Q factor is?
A.	Q = ( frac{(C_1 C_2 ) Q_1 Q_2}{Q_1 C_1 Q_2 C_2} )
B.	Q = ( frac{(C_2 C_1 ) Q_1 Q_2}{Q_1 C_1 Q_2 C_2} )
C.	Q = ( frac{(C_1 C_2 ) Q_1 Q_2}{Q_2 C_2 Q_1 C_1} )
D.	Q = ( frac{(C_2 C_1 ) C_1 C_2}{Q_1 C_1 Q_2 C_2} )
Answer» B. Q = ( frac{(C_2 C_1 ) Q_1 Q_2}{Q_1 C_1 Q_2 C_2} )

Consider a circuit consisting of two capacitors C₁ and C₂. Let R be the resistance and L be the inductance which are connected in series. Let Q₁ and Q₂ be the quality factor for the two capacitors. While measuring the Q value by the Series Connection method, the value of the Q factor is?

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