Calculate_the_value_of_rate_of_change_of_specific_energy_for_a_triangular_channel_having_depth_3.5m_and_the_side_slope_is_1H:2V._Given:V_=_2.5_m/s,_dy/dx=8.6‚Äö√†√∂‚àö‚â•10-4.$#

6.47‚Äö√†√∂‚àö‚â•10 -4 m

3.47‚Äö√†√∂‚àö‚â•10-4m

4.47‚Äö√†√∂‚àö‚â•10-4m

5.47‚Äö√†√∂‚àö‚â•10-4m

6.47‚Äö√†√∂‚àö‚â•10-4m

Calculate_the_value_of_rate_of_change_of_specific_energy_for_a_triangu

1.	Calculate_the_value_of_rate_of_change_of_specific_energy_for_a_triangular_channel_having_depth_3.5m_and_the_side_slope_is_1H:2V._Given:V_=_2.5_m/s,_dy/dx=8.6‚Äö√†√∂‚àö‚â•10^-4.$#
A.	3.47‚Äö√†√∂‚àö‚â•10<sup>-4</sup>m
B.	4.47‚Äö√†√∂‚àö‚â•10<sup>-4</sup>m
C.	5.47‚Äö√†√∂‚àö‚â•10<sup>-4</sup>m
D.	6.47‚Äö√†√∂‚àö‚â•10<sup>-4</sup>m
Answer» D. 6.47‚Äö√†√∂‚àö‚â•10<sup>-4</sup>m

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Calculate_the_value_of_rate_of_change_of_specific_energy_for_a_triangular_channel_having_depth_3.5m_and_the_side_slope_is_1H:2V._Given:V_=_2.5_m/s,_dy/dx=8.6‚Äö√†√∂‚àö‚â•10-4.$#

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Calculate_the_value_of_rate_of_change_of_specific_energy_for_a_triangular_channel_having_depth_3.5m_and_the_side_slope_is_1H:2V._Given:V_=_2.5_m/s,_dy/dx=8.6‚Äö√†√∂‚àö‚â•10^-4.$#