1.

\[{{C}_{6}}{{H}_{5}}CONHC{{H}_{3}}\] can be converted into \[{{C}_{6}}{{H}_{5}}C{{H}_{2}}NHC{{H}_{3}}\] by [AIIMS 2005]

A. \[NaB{{H}_{4}}\]
B. \[{{H}_{2}}-Pd/C\]
C. \[LiAl{{H}_{4}}\]
D. \[Zn-Hg/HCl\]
Answer» E.


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