 
			 
			MCQOPTIONS
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				| 1. | According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through centre of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) | 
| A. | IP = IG + Ah2 | 
| B. | IP = IG - Ah2 | 
| C. | IP = IG / Ah2 | 
| D. | IP = Ah2 / IG | 
| Answer» B. IP = IG - Ah2 | |