ABCD is a square. Draw a triangle QBC on side BC considering BC as base and draw a triangle PAC on AC as its base such that \[\Delta QBC\sim PAC\]. Then,\[\frac{Area\,of\,\Delta QBC}{Area\,of\ \Delta PAC}\]is equal to

ABCD is a square. Draw a triangle QBC on side BC considering BC as bas

1.	ABCD is a square. Draw a triangle QBC on side BC considering BC as base and draw a triangle PAC on AC as its base such that \[\Delta QBC\sim PAC\]. Then,\[\frac{Area\,of\,\Delta QBC}{Area\,of\ \Delta PAC}\]is equal to
A.	\[\frac{1}{2}\]
B.	\[\frac{2}{1}\]
C.	\[\frac{1}{3}\]
D.	\[\frac{2}{3}\]
Answer» B. \[\frac{2}{1}\]

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ABCD is a square. Draw a triangle QBC on side BC considering BC as base and draw a triangle PAC on AC as its base such that \[\Delta QBC\sim PAC\]. Then,\[\frac{Area\,of\,\Delta QBC}{Area\,of\ \Delta PAC}\]is equal to

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