1.

A zinc rod dipped in n molar solution of ZnSO4 has an electrode potential of -0.56 V. The salt is 98 percent dissociated at room temperature. What is the molarity of the solution? (E°(Zn+2/Zn) = -0.5 V)

A. 8.44 × 10-3 M
B. 9.44 × 10-4 M
C. 8.44 × 10-4 M
D. 9.44 × 10-3 M
Answer» E.


Discussion

No Comment Found