A variable line ?L? is drawn through \[O(0,\,\,0)\] to meet the lines \[{{L}_{1}}:y-x-10=0\] and \[{{L}_{2}}:y-x-20=0\] at the points A and B respectively. A point P is taken on ?L? such that\[\frac{2}{OP}=\frac{1}{OA}+\frac{1}{OB}.\] Locus of ?P? is

A variable line ?L? is drawn through \[O(0,\,\,0)\] to meet the lines

1.	A variable line ?L? is drawn through \[O(0,\,\,0)\] to meet the lines \[{{L}_{1}}:y-x-10=0\] and \[{{L}_{2}}:y-x-20=0\] at the points A and B respectively. A point P is taken on ?L? such that\[\frac{2}{OP}=\frac{1}{OA}+\frac{1}{OB}.\] Locus of ?P? is
A.	\[3x+3y=40\]
B.	\[3x+3y+40=0\]
C.	\[3x-3y=40\]
D.	\[3y-3x=40\]
Answer» E.

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A variable line ?L? is drawn through \[O(0,\,\,0)\] to meet the lines \[{{L}_{1}}:y-x-10=0\] and \[{{L}_{2}}:y-x-20=0\] at the points A and B respectively. A point P is taken on ?L? such that\[\frac{2}{OP}=\frac{1}{OA}+\frac{1}{OB}.\] Locus of ?P? is

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