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1. |
A thin disc of mass M and radius R has mass per unit area σ(r) = kr2 where r is the distance from its centre. Its moment of inertia about an axis going through its centre of mass and perpendicular to its plane is: |
A. | \(\frac{{M{R^2}}}{3}\) |
B. | \(\frac{{2M{R^2}}}{3}\) |
C. | \(\frac{{M{R^2}}}{6}\) |
D. | \(\frac{{M{R^2}}}{2}\) |
Answer» C. \(\frac{{M{R^2}}}{6}\) | |