A system has its open-loop transfer function of \(\frac{K}{s(s^2+6s+10)}\). The break-points are at s = -1.18 and s = -2.82, the centroid is at s = -2, while the asymptotic angles are ± 60° ± 180°. The value of K for the closed-loop system to be oscillatory and the frequency of oscillations are respectively:

A system has its open-loop transfer function of \(\frac{K}{s(s^2+6s+10

1.	A system has its open-loop transfer function of \(\frac{K}{s(s^2+6s+10)}\). The break-points are at s = -1.18 and s = -2.82, the centroid is at s = -2, while the asymptotic angles are ± 60° ± 180°. The value of K for the closed-loop system to be oscillatory and the frequency of oscillations are respectively:
A.	600 and 10 rad / sec
B.	120 and 5 rad / sec
C.	60 and 3.16 rad / sec
D.	30 and 3.16 rad / sec
Answer» D. 30 and 3.16 rad / sec

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