A projectile is projected from a point on ground with velocity of projection 'u' and angle of projection 'θ' . How much maximum height can the projectile reach ?

\(h=\frac{u^2 \sin \theta}{2g}\)

\(h=\frac{u^2 \sin^2 \theta}{2g}\)

\(h=\frac{u \sin^2 \theta}{2g}\)

A projectile is projected from a point on ground with velocity of proj

1.	A projectile is projected from a point on ground with velocity of projection 'u' and angle of projection 'θ' . How much maximum height can the projectile reach ?
A.	\(h=\frac{u \sin \theta}{2g}\)
B.	\(h=\frac{u^2 \sin^2 \theta}{2g}\)
C.	\(h=\frac{u^2 \sin \theta}{2g}\)
D.	\(h=\frac{u \sin^2 \theta}{2g}\)
Answer» C. \(h=\frac{u^2 \sin \theta}{2g}\)

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A projectile is projected from a point on ground with velocity of projection 'u' and angle of projection 'θ' . How much maximum height can the projectile reach ?

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