A pin-ended column of length L, modulus of elasticity E and second moment ofthe cross-sectional area I is loaded centrically by a compressive load P. The critical buckling load (Pcr) is given by

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TuteeHUB · Accepted Answer

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TuteeHUB · Answer

${P_{cr}} = \frac{{EI}}{{{\pi ^2}{L^2}}}$

TuteeHUB · Answer

${P_{cr}} = \frac{{{\pi ^2}EI}}{{3{L^2}}}$

TuteeHUB · Answer

${P_{cr}} = \frac{{{\pi }EI}}{{{L^2}}}$

TuteeHUB · Answer

${P_{cr}} = \frac{{{\pi ^2}EI}}{{{L^2}}}$

1.	A pin-ended column of length L, modulus of elasticity E and second moment ofthe cross-sectional area I is loaded centrically by a compressive load P. The critical buckling load (Pcr) is given by
A.	\({P_{cr}} = \frac{{EI}}{{{\pi ^2}{L^2}}}\)
B.	\({P_{cr}} = \frac{{{\pi ^2}EI}}{{3{L^2}}}\)
C.	\({P_{cr}} = \frac{{{\pi }EI}}{{{L^2}}}\)
D.	\({P_{cr}} = \frac{{{\pi ^2}EI}}{{{L^2}}}\)
Answer» E.

A pin-ended column of length L, modulus of elasticity E and second moment ofthe cross-sectional area I is loaded centrically by a compressive load P. The critical buckling load (Pcr) is given by

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