MCQOPTIONS
Saved Bookmarks
| 1. |
A particle starts moving from rest with an acceleration in a fixed direction. If its acceleration at time t be(a bt2),where a and b are positive constants then which one is correct? |
| A. | [v]<sub>max</sub> = 4a a/3 b |
| B. | [v]<sub>max</sub> = 2a a/3 b |
| C. | [v]<sub>max</sub> = 2a a/3 b |
| D. | [v]<sub>max</sub> = 4a a/3 b |
| Answer» C. [v]<sub>max</sub> = 2a a/3 b | |