MCQOPTIONS
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| 1. |
A particle starts moving from rest with an acceleration in a fixed direction. If its acceleration at time t be(a – bt2),where a and b are positive constants then which one is correct? |
| A. | [v]max = 4a√a/3√b |
| B. | [v]max = 2a√a/3√b |
| C. | [v]max = 2a√a/3√b |
| D. | [v]max = 4a√a/3√b |
| Answer» C. [v]max = 2a√a/3√b | |