A particle starts from rest with a constant acceleration α m/sec2 and after some time it decelerates at a uniform rate of β m/sec2 till it comes to rest. If the total time taken between two rests positions is t, then maximum velocity acquired by the particle would be:

\(\left( {\frac{{\alpha + \beta }}{{\alpha - \beta }}} \right)t\)

\(\frac{{\alpha + \beta }}{2}t\)

\(\frac{{\alpha - \beta }}{2}t\)

\(\left( { \frac{{\alpha \beta }}{{\alpha + \beta }}} \right)t\)

A particle starts from rest with a constant acceleration α m/sec2 and

1.	A particle starts from rest with a constant acceleration α m/sec2 and after some time it decelerates at a uniform rate of β m/sec2 till it comes to rest. If the total time taken between two rests positions is t, then maximum velocity acquired by the particle would be:
A.	\(\frac{{\alpha + \beta }}{2}t\)
B.	\(\frac{{\alpha - \beta }}{2}t\)
C.	\(\left( { \frac{{\alpha \beta }}{{\alpha + \beta }}} \right)t\)
D.	\(\left( {\frac{{\alpha + \beta }}{{\alpha - \beta }}} \right)t\)
Answer» D. \(\left( {\frac{{\alpha + \beta }}{{\alpha - \beta }}} \right)t\)

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A particle starts from rest with a constant acceleration α m/sec2 and after some time it decelerates at a uniform rate of β m/sec2 till it comes to rest. If the total time taken between two rests positions is t, then maximum velocity acquired by the particle would be:

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