A particle of mass m is moving along a trajectory given byx = x0 + a cos ω1ty = y0 + b sin ω2tThe torque, acting on the particle about the origin, at t = 0 is:

\(m\left( { - {x_0}b + {y_0}a} \right)\omega _1^2\hat k\)

\( + m{y_0}a\omega _1^2\hat k\)

\( - m\left( {{x_0}b\omega _2^2 - {y_0}a\omega _1^2} \right)\hat k\)

A particle of mass m is moving along a trajectory given byx = x0 + a c

1.	A particle of mass m is moving along a trajectory given byx = x0 + a cos ω1ty = y0 + b sin ω2tThe torque, acting on the particle about the origin, at t = 0 is:
A.	\(m\left( { - {x_0}b + {y_0}a} \right)\omega _1^2\hat k\)
B.	\( + m{y_0}a\omega _1^2\hat k\)
C.	Zero
D.	\( - m\left( {{x_0}b\omega _2^2 - {y_0}a\omega _1^2} \right)\hat k\)
Answer» C. Zero

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A particle of mass m is moving along a trajectory given byx = x0 + a cos ω1ty = y0 + b sin ω2tThe torque, acting on the particle about the origin, at t = 0 is:

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