1.

A particle is projected with velocity u at an inclination θ with the horizontal. Then Maximum height (H) attained is

A. \(\frac{u^2 sin^2\theta}{g}\)
B. \(\frac{2u^2 sin^2\theta}{g}\)
C. \(\frac{u^2 sin^2\theta}{2g}\)
D. \(\frac{u^2 sin2\theta}{g}\)
Answer» D. \(\frac{u^2 sin2\theta}{g}\)


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