A particle is projected at an angle θ to the horizontal and it attains a maximum height H. The time taken by the projectile to reach the highest point, of its path is

\(\frac{{\sqrt {2H\sin \theta } }}{g}\)

\(\frac{{\sqrt {2H} }}{{\sin \theta }}\)

A particle is projected at an angle θ to the horizontal and it attain

1.	A particle is projected at an angle θ to the horizontal and it attains a maximum height H. The time taken by the projectile to reach the highest point, of its path is
A.	\(\frac{{\sqrt H }}{g}\)
B.	\(\sqrt {\frac{{2H}}{g}} \)
C.	\(\frac{{\sqrt {2H\sin \theta } }}{g}\)
D.	\(\frac{{\sqrt {2H} }}{{\sin \theta }}\)
Answer» C. \(\frac{{\sqrt {2H\sin \theta } }}{g}\)

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A particle is projected at an angle θ to the horizontal and it attains a maximum height H. The time taken by the projectile to reach the highest point, of its path is

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