A material‚Äö√Ñ√∂‚àö√ë‚àö¬•s mass is given by the equation, m = 32P0.02/T0.5, where T is in Kelvin, m is in Kg and P is in mm Hg, what is the mass of material at 127oC, use A = 10, B = 6 X 103 and C = 0?$

A material‚Äö√Ñ√∂‚àö√ë‚àö¬•s mass is given by

1.	A material‚Äö√Ñ√∂‚àö√ë‚àö¬•s mass is given by the equation, m = 32P^0.02/T^0.5, where T is in Kelvin, m is in Kg and P is in mm Hg, what is the mass of material at 127^oC, use A = 10, B = 6 X 10³ and C = 0?$
A.	1.44 Kg
B.	1.69 Kg
C.	1.96 Kg
D.	2.25 Kg
Answer» B. 1.69 Kg

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A material‚Äö√Ñ√∂‚àö√ë‚àö¬•s mass is given by the equation, m = 32P0.02/T0.5, where T is in Kelvin, m is in Kg and P is in mm Hg, what is the mass of material at 127oC, use A = 10, B = 6 X 103 and C = 0?$

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A material‚Äö√Ñ√∂‚àö√ë‚àö¬•s mass is given by the equation, m = 32P^0.02/T^0.5, where T is in Kelvin, m is in Kg and P is in mm Hg, what is the mass of material at 127^oC, use A = 10, B = 6 X 10³ and C = 0?$