A= ( left[ begin{array}{c c r r}3 & 2 & 1 4 & 5 & -8 10 & 0 & 5 end{array} right] )Then det (A) =

A= ( left[ begin{array}{c c r r}3 & 2 & 1 4 & 5 & -8 10 & 0 & 5

1.	A= ( left[ begin{array}{c c r r} 3 & 2 & 1 4 & 5 & -8 10 & 0 & 5 end{array} right] )Then det (A) =
A.	120
B.	-80
C.	-175
D.	0
Answer» D. 0