A diode circuit is so arranged that when the switch is open it's KVL givesRi+ 1/C ∫i dt = 0When the switch is closed,Ri+ 1/C ∫i dt = VsVs is the dc supply voltage.The diode is so connected that it is forward biased when switch is closedThe circuit is mostly likely be a

• A. diode in parallel with Vs, switch, R & C
• B. diode in series with R, than parallel with Vs & C
• C. diode in series with the switch, R, C & Vs
• D. diode in series with R,C & Vs with the switch connected in parallel across Vs