A 50 Hz 6 pole 1000 MVA ,44 kV synchronous generator is supplying a full load at the 0.8 lagging power factor. Its output is reduced by 50% due to an electrical fault. So what will be the accelerating torque of the generator immediately after the electrical fault, ignoring the loss and considering that the primary inductive current that drives it is constant?

A 50 Hz 6 pole 1000 MVA ,44 kV synchronous generator is supplying a fu

1.	A 50 Hz 6 pole 1000 MVA ,44 kV synchronous generator is supplying a full load at the 0.8 lagging power factor. Its output is reduced by 50% due to an electrical fault. So what will be the accelerating torque of the generator immediately after the electrical fault, ignoring the loss and considering that the primary inductive current that drives it is constant?
A.	6/π
B.	24/π
C.	12/π
D.	2/π
Answer» D. 2/π

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A 50 Hz 6 pole 1000 MVA ,44 kV synchronous generator is supplying a full load at the 0.8 lagging power factor. Its output is reduced by 50% due to an electrical fault. So what will be the accelerating torque of the generator immediately after the electrical fault, ignoring the loss and considering that the primary inductive current that drives it is constant?
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